Пример выполнения работы (структура боксер):

# include <stdio.h>

# include <conio.h>

# include <iostream.h>

const LEN = 40,LEN3=120;

struct boxer {char fam[LEN] ,ima[LEN],otch[LEN];

unsigned rost,pobed,poragen;

float wes;

Void prn () const

{printf ("\n%s %s %s\n",fam,ima,otch);

printf ("wes %g\n",wes);

printf ("rost %d\n",rost);

printf ("wstrech %d\n",pobed+poragen);

printf ("pobed %d\n",pobed);

printf ("poragen %d\n",poragen);

}

int operator > (boxer a) const

{float dolja1,dolja2;

dolja1=float(pobed)/(pobed + poragen);

dolja2=float(a.pobed)/(a.pobed + a.poragen);

return dolja1>dolja2;

}

};

Int main()

{textbackground(1);textcolor(14);

clrscr();

boxer a,b={"Deev","Ivan","Petrovich",183,11,1,77} ;

boxer * a1=&a,* b1=&b;

cputs ("fam = ");gets(a1->fam );

cputs ("ima = ");gets(a.ima );

cputs ("otch = ");gets(a.otch );

cputs ("wes = ");scanf("%f",&a.wes);

cputs ("rost = ");scanf("%d",&a.rost);

cputs ("pobed = ");scanf("%d",&a.pobed);

cputs ("poragen = ");scanf("%d",&a.poragen);

a1->prn();

b1->prn();

if (a>b) cout << a.fam << " effektivnee " << b1->fam;

else cout << b.fam << " effektivnee " << a1->fam;

getch();

return 0;

}