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1. Теорема добутку ймовірностей та наслідки з неї.

Theorem of product

The probability of the product of two dependent events A and B is equal to the probability of one of them multiplied be conditional probability of the other.

P (AB) = P(A)*PA(B) – if A appears 1st

P (AB) = P(B)*PB(A) – if B appears 1st

Proof

Let n be the total number of incompatible equally possible outcomes

m – the number of outcomes leading to occurrence of the event A

l – number of outcomes leading to occurrence of the event B

k - the number of outcomes leading to occurrence of the event A and B together.

P(A*B) = k/n=(k*m)/(n*m)=(m/n)*(k/m)=P(A)*PA(B)

P(A*B)=(k*l)/(n*l)=(l/n)*(k/l)=P(B)*PB(A)

Consequence

A1,A2,A3…An – dependent events, then the probability of their product P(A1,A2…An) equals P(A1)*PA1(A2)*PA1A2(A3)*…*PA1A2An-1(An)

Properties of conditional probability:

  1. 0<=PA(B)<=1

  2. If A and B are independent , then

  3. P(A*B)=P(A)*P(B), PA(B)=P(B)

2. Теорема суми ймовірностей та наслідки з неї

The addition theorem

The probability of the sum of two events A and B is equal to the sum of their probabilities minus the probability pf their product.

P(A+B)=P(A)+P(B)-P(A*B)

Proof

n – total number of equally probable and incompatible outcomes.

m – number of outcomes leading to the occurrence of event A.

l – number of occurrence of the event B

k – number of outcomes leading to the occurrence A and B together, when the probability of sum A and B is equal by classic definition.

P(A+B) = (m+l-k)/n=m/n +l/n-k/n = P(A)+P(B)-P(A*B)

Consequence 1

If A1,A2,…An from the full group of events, then the probability of their sum is 1.

P(A1+A2+…An)=P(A1)+P(A2)+…+P(An)=1

Consequence 2

If events A and А̅ are opposite, then the probability of their sum is equal:

P(A) +P(A̅)=1

3. Теорема (формула повної імовірності)

Formula of total probability

Let event A can occur only together with events H1, H2, H3,…Hn (with one of this events), H1, H2, H3,… Hn will call hypothesis.

Probabilities of hypothesis are known P(H1),P(H2),P(H3),…P(Hn) and also conditional probabilities of event A is known PH1(A), PH2(A),… PHn(A).

Events H1, H2, H3,… Hn form full group of probabilities.

P(H1)+P(H2)+…+P(Hn)=1

Event A can occur only together with H1, H2, … Hn , consequently event A will be the sum of following events.

A=A*H1+A*H2+A*H3+…+A*Hn

To find P(A) we use the theorem of sum of probability. These events are incompatible.

P(A)=P(A*H1)+P(A*H2)+…+P(A*Hn)

Let’s use the theorem of product: events A and H1,H2,…Hn are dependent, so

P(A)= P(H1)*PH1(A)+ P(H2)*PH2(A)+…+ P(Hn)*PHn(A) –formula of total probability.

4. Теорема (формули Байєса).

Bayes formula

In practice we are interested in full group of incompatible vents H1,H2,…Hn, which probabilities are known P(Hi), i=1̅̅..̅n. These events are not observable, but we may observe the conditional probabilities. If event A already appeared, after event A appeared we can observe conditional probabilities of hypothesis.

PA(H1),PA(H2),…,PA(Hn)

PA(H1)=P(H1)*PH1(A) ; PA(H2)= P(H2)*PH2(A)

P(A) P(A)

Or using total formula of probability:

PA(H1)=P(H1)*PH1(A)

∑P(Hi)*PHi(A)

i=1…n

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