
Variant 11
In order to compare the accuracy of two lathes two samples have been
made. Their volumes are:
.
The following results have been received:
1st sample (X) |
1.08 |
1.10 |
1.12 |
1.14 |
1.15 |
1.25 |
1.36 |
1.38 |
1.40 |
1.42 |
2nd sample (Y) |
1.11 |
1.12 |
1.18 |
1.22 |
1.33 |
1.35 |
1.36 |
1.38 |
|
|
Is it possible to suppose that the lathes have the same accuracy, if we consider the confidence level α=0.1 (the competing hypothesis lies in lathes accuracy difference).
The accuracy of a lathe is verified by variance of
a product size. It must not exceed
=0.1.
We made a random product sample. The results
are following:
Product size |
3.0 |
3.5 |
3.8 |
4.4 |
4.5 |
Frequencies |
2 |
6 |
9 |
7 |
1 |
We need to verify if the lathe can provide the needed accuracy. The confidence level is 0.05.
The average weight of items made on the 1st lathe equals x=130g. (sample volume n=30). The average weight of items made on the 2nd lathe equals y=125g. (sample volume n=40)..Universal variances are known: D(X)=60 g2, D(Y)=80 g2. We need to verify the following null hypothesis (confidence level is 0.05): E(X)=E(Y). The competing hypothesis is . The random variables X,Y are normally distributed, and the samples are independent.
We have two independent small samples. Their
volumes are n=10, m=8, and they were selected from normal universal
sets. We found sampling averages
and corrected sampling variances
.
The confidence level is α=0.01.
We need to verify the null hypothesis
when
the competing hypothesis is
.
X is normally distributed. Sample volume n=100, sampling average =35, the corrected standard deviation s=20. Estimate the unknown mean using confident intervals. Reliability =0.95.