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Roberts, Caserio - Basic Principles of Organic Chemistry (2nd edition, 1977)

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19-8 Prochirality

889

citric acid, 13, is converted by enzymes (from rat liver) to the carbonyl of 2-oxobutanedioic acid:

The notation prochiral center is useful in molecules that already have one or more chiral centers. Development of chirality from prochirality in such cases would lead to diastereomers, as shown in the conversions of 14 and 15:

 

I

 

 

H-C-OHI

 

H-C-OHI

H - C w c h i r a l center

 

+

 

I

 

-

1

I

H-C&

prochiral center

 

H-C-OH

 

HO-C-H

 

I

(diastereotopic

 

I

 

I

 

C H 3

hydrogens)

 

CH,

 

CH.3

 

14

 

 

 

 

 

 

 

diastereomers

 

 

 

 

C N

 

C N

H\

/0

- prochiral center

 

I

 

I

 

C-

I

H-C-OH

+

HO-C-H

 

I

 

H-C-OH

I

H-C-OH

 

 

 

H-C-OH

 

/

chiral center

 

I

 

I

 

CH.3

 

 

CH.3

CH.3

 

15

 

 

 

diastereomers

Exercise 19-13" Designate which

of the following structures are chiral, prochiral,

and/or achiral. Specify which carbon atoms are prochiral centers.

a.

ethenylbenzene (styrene)

f.

butanedioic acid, (CH2C02H),

b.

cis-2-butene

g.

2-methylbutanedioic acid, CH,CHC02H

c.

2-propanone (acetone)

 

I

d.

2-butanone

 

CH2C02H

h. 1-chloro-2-phenylethane

e.

glycine, H2NCH2C02H

 

 

898

19 More on Stereochemistry

Exercise 19-14* One part of the citric

acid cycle (Sections 18-8F and 20-108) in

metabolism converts 2-oxobutanedioic acid by way of citric acid to 2-oxopentanedioic acid:

If the 4-carboxyl carbon of the 2-oxobutanedioic acid is enriched in 73C,only the I-carboxyl carbon of the 2-oxopentanedioic acid contains excess l3C. Explain in general terms how the intermediate citric acid must be labeled to have the I3C turn up in the I-carboxyl of the 2-oxopentanedioic acid.

19-9 OPTICAL ROTATORY DISPERSION.

CIRCULAR DICHROISM

Optical rotations usually are measured at just one wavelength, namely 589.3 nm, simply because sodium-vapor lamps provide an especially convenient source of monochromatic light. Measurements at other wavelengths are less easily made without speciaIized instruments, with which relatively few laborator-ies are currently equipped. Nevertheless, much information has been obtained about structure, conformation, and configuration of organic compounds from measurements of optical rotation as a function of wavelength (i.e., optical ro- tatory dispersion).

Like other phenomena involving interactions between electromagnetic radiation and organic molecules, as in infrared, ultraviolet, and nmr spectroscopy, optical rotatory dispersion curves often are quite sensitive to small changes in structure. As an example, the rotatory dispersion curves for enantiomers of L'I's- and t~aizs-I0-methyl-2-decalones, 16 and 17,are reproduced in Figure 19-7:

Only a small positive rotation is observed for the particuiar enantiomers at the wavelength of the sodium line (589.3 nm) compared to the large, both positive and negative, rotations found at wavelengths between 270 nrn and 400 nm. If we measure the rotations as a ftrnction of wavelength and if, as we approach shorter wavelengths, the rotation rises to a mnxii-r~urnbefore changing sign, as it does with the trans isomer, 17, then the compound is said to exhibit a

19-9 Optical Rotatory Dispersion. Circular Dichroism

Figure 19-7 Rotatory dispersion curves for cis-10-methyl-2-decalone, 16, and trans-10-methyl-2-decalone 17. (By permission from C. Djerassi, Optical Rotatory Dispersion, McGraw-Hill Book Co., New York, 1960.)

positive Cotton effect. The opposite behavior, as with the cis isomer, 16, is called a negative Cotton effect. The wavelength at the center point for the very rapid change in rotation for 17 is 300 nm and corresponds to the n --+ 7 ~ . absorption maximum of the carbonyl group in the ultraviolet absorption curve of the same compound. Thus excitation of the carbonyl group by absorption of ultraviolet light and strong rotatory dispersion of polarized light are associated phenomena. In fact, when a substance exhibits a Cotton effect, not only does it transmit clockwise and counterclockwise circularly polarized light

with unequal

velocities

(Section 19-I), it also absorbs the two forms of light

unequally.

 

 

This

means

that the

molar extinction coefficients of the two enantiomers

( E ~and

E,) are unequal

in circularly polarized light. These differences in ab-

sorption (el and E,) can be measured as a function of wavelength, and the curves obtained are called circular dichrois~ncurves. They have positive or negative signs (Cotton effect) just as for optical rotatory dispersion curves.

Most of the research on optical rotatory dispersion to date has been with optically active ketones because the carbonyl chromophore conveniently has a weak absorption band in the 300 nm region. Compounds wlth chromophores that absorb light strongly in the ultraviolet usually are unsatisfactory for rotatory dispersion measurements because insufficient incident light is transmitted to permit measurement of optical rotation. Weak absorption bands below about 2 10 nm have not been exploited because of experimental difficulties in making the necessary measurements.

Many rotatory dispersion curves have been obtained for optically active ketones derived from steroids and triterpenes, which are monocyclic, bicyclic, and open-chain compounds. Enough data have been accumulated so that the various shapes and magnitudes of the curves are recognized as characteristic of particular structural features. A good illustration is provided by the rotatory

19 More on Stereochemistry

[ a ] X

Figure 19-8 Rotatory dispersion curves for trans-8-methylhydrindan-5- one, 19, cis-8-methylhydrindan-5-one, 18, and B-norcoprostan-3-one, 20a. (By permission from C. Djerassi, Optical Rotatory Dispersion, McGraw-Hill Book Co., New York, 1960.)

dispersion curves for the cis- and tmns-8-methylhydrindan-5-ones, 18 and 19, which are shown in Figure 19-8:

cis-ring junction, 1 8

trans-ring junction,19

The remarkable differences in these curves are due to changes in the environment of the carbonyl groups arising from the different configurations of the hydrogens at the ring junctions. Because the rotatory dispersion curve of the closely related structure 20a is very similar to that of the cis-hydrindanone, 18, the rings labeled A and B in 20a can be inferred also to be cis oriented (see Figure 19-8):

19-10 Asymmetric Synthesis

893

Rotatory dispersion curves often are helpful in establishing configurations; thus the relative configurations of compounds 18 and 20a must be the same because, if they were not, the two curves would resemble mirror images of one another. Therefore, if the absolute configuration of 18 corresponds to the formula shown, then compound 2023 has the configuration shown and not 20b.

19-10 ASYMMETRIC SYNTHESIS

If one could prepare 2-hydroxypropanenitrile from ethanal and hydrogen cyanide in the absence of any chiral reagent and produce an excess of one enantiomer over the other, this would constitute an absolute asymmetric sym- thesis-that is, creation of preferential chirality (optical activity) in a symmetrical environment from symmetrical reagents:

C N

 

 

 

CN

I

H@

 

H@

I

HO-C-H

+----

 

 

H-C-OH

I

 

 

 

I

CH3

 

,

 

CM3

L-2-hydroxypropanenitrile,21

'"cN@

D-2-hydroxypropanenitri ~ e22,

This obviously is unlikely for the given example because there is no reason for cyanide ion to have anything other than an exactly equal chance of attacking above o r below the plane of the ethanal molecule, producing equal numbers of molecules of the enantiomers, 21 and 22. However, when a chiral center is created through reaction with a dissymmetric (chiral) reagent, we should not expect an exactly 1: 1 mixture of the two possible isomers. Fo r example, in an aldol-type addition (Section 18-8E) of a chiral ester to a prochiral ketone the two configurations at the new chiral center in the products 23 and 24 are not equally favored. That is to say, asymmetric synthesis is achieved by the influence of one chiral center (R'k) on the development of the second:

C6H5

0

 

C6H5 CHZCOpR*

CtH5 ,,OH

\

II

base \

.,""

+ c.'"

C=O

+ CH,COR* -

F\

/

 

 

C 6 , 'cH,cO,R*

CH3

 

CH,

OH

 

 

 

 

 

19 More on Stereochemistry

You will notice that the reaction products 23 and 24 are diastereomers, not enantiomers. Asymmetric synthesis can be achieved only when the possible transition states for reaction are diastereomeric because they then will have different energies and will lead to products at different rates. The larger the energy difference between diastereomeric transition states, the more stereochemical preference there will be for one chirality over the other.

The degree of stereochemical control displayed by the first chiral center usually depends on how close it is to the secondthe more widely separated they are, the less steric control there is. Another factor is the degree of electronic control. If all the groups are very much the same electrically and sterically, not much stereochemical control is to be expected. Even when the chiral centers are close neighbors, asymmetric induction is seldom 100% efficient in simple molecules. In biochemical systems, however, asymmetric synthesis is highly efficient.

The stereospecificity of living organisms is imperative to their efficiency. The reason is that it is just not possible for an organism to be so constructed as to be able to deal with all of the theoretically possible isomers of molecules with many asymmetric centers. Thus a protein molecule not uncommonly has 100 or more different asymmetric centers; such a molecule would have 21°0or 10" possible optical isomers. A vessel with a capacity on the order of lo7liters would be required to hold all of the possible stereoisomeric molecules of this structure if no two were identical. An organism so constituted as to be able to deal specifically with each one of these isomers would be very large indeed.

Exercise 19-15 Write structures showing the configuration of each of the possible products to be expected from the following reactions.

CHO

I

I

d. H-C-OH + HCN

I

- \

RhL3"'C13,H2

e.

benzene-ethanol '

/C=CH2

~64

 

(L" is a chiral phosphorus ligand attached to Rh)

19-11 Racemization

895

Exercise 19-16 a. When (+)-a-pinene, 25, reacts with diborane, a dialkylborane, 26, is formed:

When 26 reacts with cis-2-butene in CH30CH2CH,0CH2CH20CH3as solvent, a trialkylborane is produced. Oxidation of this product with H,02 yields isopinocampheol, 27, and (-)-2-butanol in 76% enantiomeric purity. Write equations for these reactions and account for the observed asymmetric synthesis.

b. 3-Methylcyclopentene can be partially resolved by reaction with less than an equimolar amount of 25. The residual alkene has an optical activity corresponding to about 65% enantiomeric purity. Explain how this partial resolution arises. Why is it necessary to use less than an equivalent of 25?

19-11 RACEMIZATION

Optically active biphenyl derivatives (Section 13-5A) are racemized if the two aromatic rings at any time pass through a coplanar configuration by rotation about the central bond. This can be brought about more or less easily by heat, unless the 2,2'-ortho substituents are very large.

The way in which compounds with asymmetric carbon atoms are racemized is more complicated. One possibility would be for a tetrahedral chiral carbon attached to four groups to become planar and achiral without breaking any bonds. Theoretical calculations indicate that this is not a likely process for chiral tetravalent carbon but, as we will see, it does occur with chiral carbon and other chiral atoms that are attached to three groups:

planar carbon

I I

Optically active carbonyl compounds of the type -CH-C=O, in which the alpha carbon is asymmetric, are racemized by both acids and bases, and from

19 More on Stereochemistry

Section 17-1 we can be sure that this is related to enolization. Formation of either the en01 or the enolate anion will destroy the asymmetry of the a carbon so that, even if only trace amounts of en01 are present at any given time, eventually all of the compound will be racemized. However, the mechanism requires both that there be an a hydrogen and that the center of symmetry be located at this a! carbon. Otherwise, acids and bases are ineffective in catalyzing racemization.

Acid-catalyzed enolization

PH

H, 7

H,

/P

\

 

 

R2

-- R 1 /

 

 

---c-C

\ t-L

,C=C\

-.--C-C

 

Ri/

 

\R

Rl

R

Rl

R

R2

The racemization of an optically active secondary halide with the chiral carbon carrying the halogen (e.g., 2-chlorobutane) may occur ih solution and, usually, the more polar and better ionizing the solvent is, the more readily the substance is racemized. Ionization of the halide by an S,1 process probably is responsible, and this certainly would be promoted by polar solvents (see Section 8-6). All indications are that an alkyl carbocation once dissociated from its accompanying anion is planar; and, when such an ion recombines with the anion, it has equal probability of forming the D and L enantiomers:

CH,

I -

Optically active halides also can be racemized by an S,2 mechanism. A solution of active 2-chlorobutane in 2-propanone containing dissolved lithium chloride becomes racemic. Displacement of the chloride of the halide by chloride ion inverts configuration at the atom undergoing substitution (see Section 8-5). A second substitution regenerates the original enantiomer. Eventually, this back-and-forth process produces equal numbers of the D and L forms; the substance then is racemic:

19-11 Racemization

897

Asymmetric alcohols often are racemized by strong acids. Undoubtedly, ionization takes place, and recombination of the carbocation with water leads to either enantiomer:

CH3

 

cw3

H-C-OH

H@

1 0

T----+

H-C-OH,

In contrast to halides, alcohols, and carbonyl compounds, hydrocarbons may be extremely difficult to racemize. This is particularly true for a compound with a quaternary asymmetric center, such as methylethylpropylbutylmethane, 28, which has no "handle" to allow one to convert the asymmetric carbon to a symmetric condition by simple chemical means:

However, hydrocarbons that have a hydrogen atom at the asymmetric carbon may be racemized if they can be converted either to carbocations or to carbanions. The ease of carbanion-type racemization will depend on the acidity of the attached hydrogen and on the stereochemical stability of the intermediate carbanion that is formed. If the configuration of the carbanion intermediate inverts, racemization will result (also see Section 6-4E):

The carbocation type of racemization of an optically active hydrocarbon can occur by the exchange reaction described in Section 10-9.

19 More on Stereochemistry

Additional Reading

G. Natta and M. Farina, Stereochemistry, Harper and Row, New York, 1972

K.Mislow, Introduction to Stereochemistry, W. A. Benjamin, Inc., Menlo Park, Calif,, 1965.

E.L. Eliel, Stereochemistry of Carbon Compounds, McGraw-Hill Book Co., New York, 1962.

J.D. Morrison and H. S. Mosher, Asymmetric Organic-Reactions, Prentice-Hall, Englewood Cliffs, N.J., 1971.

W.~ l w o r t hStereochemistry, and its Application in Biochemistry, Wiley-Interscience, New York, 1972.

A valuable series of referenced articles on stereochemistry may be found in Topics in Stereochemistry, Volumes 1-8, N. L. Allinger and E. L. Eliel, Ed., Wiley-Interscience, New York, 1967-1 975.

V. Prelog, "Chirality in Chemistry," Science 193, 17 (1976).

Supplementary Exercises

v

19-17 Which of the following projection formulas represent the same isomer? Write each in its proper form as a Fischer projection formula of 3-amino-2-butanol.

CH3

H

OH

I

I

I

H-C-OH

CH3-C-OH

CH,-C-H

I

I

I

H-C-NH,

CH3-C-NH2

H2N-C-H

I

I

I

CH3

H

CH3

I

I

I

H-C-OH

H-C-NH2

H2N-C-CH3

I

I

I

CH3

CH3

H

19-18 Draw Fischer projection formulas for all the possible different configuration isomers of the following substances:

a.1,2,3,4-tetrachlorobutane

b.methylethylpropyl boron

c.2,3-dibromopropanoic acid

d.3-bromo-2,5-hexanediol

e.methyl hydrogen tartrate (a half-ester)

6. sec-butyl lactate

g. C02CH,

AI -i"\ CH,

CH.o/

I

C02CH3

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