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Roberts, Caserio - Basic Principles of Organic Chemistry (2nd edition, 1977)

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Additional Reading

The reaction is speeded up greatly by addition of small amounts of 2-methyl- propene. Explain. Would you expect any significant formation of D2S04when the reaction is carried out in the presence of 2-methylpropene? Why?

Additional Reading

M.L. Poutsma, "Chlorination of Unsaturated Compounds in Non-Polar Media," Science 157, 997 (1967).

C.Walling and E. S. Huyser, "Free-Radical Additions to Olefins to Form Carbon-Carbon Bonds," Organic Reactions 3, 91 ( I963).

F.N. Stacey and J. F. Harris, Jr., "Formation of Carbon-Hetero Atom Bonds by FreeRadical Chain Additions to Carbon-Carbon Multiple Bonds," Organic Reactions 3, 150 (1963).

H. Saltzman, "Arthur Lapworth: The Genesis of Reaction Mechanism," J. Chem. Educ. 49, 750 (1972).

N. lsenberg and M. Grdinic, "A Modern Look at Markovnikov'sRule and the Peroxide Effect," J. Chem. Educ. 46, 601 (1969).

W. R. Dolbier, Jr., "Electrophilic Additions to Alkenes (Research Summary)," J. Chem. Educ. 46, 343 (1969).

Supplementary Exercises

10-32 For each of the following groups of substances designate which is the strongest electrophile and which is the strongest nucleophile. Give your reasoning

a. H 2 0 H30@ HO@

b. 1,

0

l0 H,OI

0

e. HO-NO, H,O-NO, @NO2 @O-N02

f. HF, HF + SbF,, SbF,@, F@

10 Alkenes and Alkynes I. Ionic and Radical Addition Reactions

10-33 Identify the nucleophile and the electrophile in each of the following reactions:

0

b. H2C=CH2 + Br, t--..H2C(Br)CH2+ B P

10-34 lndicate what reagents and conditions would convert cyclohexene to the following derivatives:

10-35 Use the

electronegativity chart (Figure 10-11) to predict how the indicated

bond would be expected to be polarized for each of the following compounds:

a.

H3C-H

f.

H2N-SCH,

b.

H3Si-H

g.

H2N-OH

c.

CH3-Li

h.

H2N-Br

d.

CH3-MgCH3

i.

H2P-CI

e.

CH3S-CI

j.

(CH3),Si-CI

10-36 Draw structures for the major products of each of the following reactions. lndicate the stereochemistry of the product, where possible. (D is deuterium, the hydrogen isotope of mass 2.)

a- (,:I + Br2 -CCI,

+ CH CI

c. cis-1-phenylpropene DBr 2

Supplementary Exercises

 

II

d. C,H5C-CCH, + HCI + CH3-C-OH (solvent) --+

1. HgCI,

2. DCI ,

e. CH3C-CH

 

10-37 Why is molecular fluorine generally unsatisfactory as a reagent to convert alkenes to 1,2-dif1uoroalkanes?

10-38 Why does the addition of chlorine to 2-pentene in methanol give a mixture of the following products?

2,3-dichloropentane (16%)

2-chloro-3-methoxypentane (35%)

3-chloro-2-methoxypentane (49%)

10-39 Suggest a mechanism to account for the following reaction:

10-40 In Section 1-11, the addition of bromine to tetrachloroethene was reported to be catalyzed by aluminum bromide. What is the function of aluminum bromide in this addition?

10-41 Evaluate (show your reasoning) the possibility that the following reaction will give the indicated product:

If you do not think the indicated product would be important, write the structure(s) of the product(s) you think would be more likely to be found.

10-42 2-Methylpropene reacts with ethene and hydrogen chloride under polar conditions to yield I-chloro-3,3-dimethylbutane. Show a mechanism for this reaction that is consistent with the reactants, conditions, and product. Give your reasoning.

10 Alkenes and Alkynes I. Ionic and Radical Addition Reactions

10-43 2-Methylpropane (containing traces of 2-methylpropene) is converted by a large excess of deuteriosulfuric acid (D,SO,) rather rapidly to 2-methylpropane with only nine deuteriums.

a.Write a polar mechanism for this hydrogen-exchange reaction that is in harmony with the known chemical properties of sulfuric acid and that predicts exchange of no more than nine of the ten hydrogens of 2-methylpropane.

b.Explain how 2-methylpropane-D, can be formed more rapidly than 2-methyl- propane-D, with n < 9 in the early stages of the reaction.

10-44 Suggest how each of the following compounds may be prepared. Assume any necessary starting hydrocarbons are available. Specify the reaction conditions as closely as possible and indicate when isomer separations may be necessary.

e. C H CHCH,

5 l

 

OH

 

f.

CI,CHCHCI,

 

 

 

0

g.

CH,=CH-0-C-CH,

II

(ethenyl ethanoate)

10-45 Calculate AH0values for the following reactions in the gas phase per mole of the principal reactants, using the bond-energy table (Table 4-3).

10-46 Use bond energies (Table 4-3) to investigate the possibility of adding water to propene, using peroxide (ROOR) catalysts. It has been reported that y rays, such as from a cobalt-60 source, decompose water into H. and HO-.Could such radiation initiate a chain-addition reaction of water to propene? How about a nonchain mechanism (i.e.,one y-ray photon per molecule of reacting propene)? In a nonchain mechanism, would you expect to get I-propanol or 2-propanol? What other products may be obtained in a nonchain reaction? Give your reasoning in detail.

Supplementary Exercises

10-47 Use bond energies (Table 4-3) to investigate the energetic feasibility of adding ammonia (NH,) to an alkene by a radical-chain mechanism with the aid of a peroxide (ROOR) catalyst. What product would you expect to obtain from propene and ammonia by a radical mechanism of addition?

10-48 Draw an energy diagram similar to Figure 10-10 for the progress of a two-step

reaction A + BC eA-B-C

D

A-B

+C-D

in which the first step is a rapidly

-+

established equilibrium and the second step is

the slow or rate-determining step.

Label the diagram to show what part represents the transition state, reaction intermediate, overall energy of activation (AHt), and overall standard enthalpy change (AH0) for the process A -I- BC + D +AB +CD. Assume that the overall equilibrium constant, K, > 1.

10-49 Complete the following equations showing the structures of the expected products under the reaction conditions:

 

 

 

 

 

0

 

 

 

ROOR

 

 

 

11

+ BrCCI,

ROOR

a. CH2=CHCN + (C,H,),SiH - f.

HC=CCH,OCCH,

-

 

 

g. CH,C=CH

 

hv

 

 

 

+ CF31---+

 

.

ROOR

 

 

 

 

 

 

+ HOCH2CH2SH-

 

 

 

 

 

 

 

 

 

 

 

 

ROOR

 

 

ROOR

h. 1-hexene +

 

-

 

C. flCH3+ HSCH2C02H------+

+

 

-

 

v

i.

1-hexene

 

0ROOR

 

+ROOR

d.I-octene CI,SiH -----+

ROOR

ROOR

e. (CH,),C=CH, -I- CCI, -

j. 1-hexene + CH3C02H------+

10-50 This problem illustrates one of the complications that can arise in radicaladdition reactions.

Cyclohexene reacts with bromotrichloromethane at 40" in the presence of small qua~ttitiesof peroxides to give a mixture of prodhcts: 2-bromo-I-trichloro- methylcyclohexane (67%) and 3-bromocyclohexene (33%). Account for the formation of both of these products under the reaction conditions.

10-51 Describe how you would prepare each of the following compounds from the indicated starting materials. Assume that any other necessary inorganic or organic reagents are available. Specify the reagents and reaction conditions as closely as possible.

a. H02CCH2CH2CH2CH2C02H(hexanedioic acid) from CH3C02H (ethanoic acid) and HC=CH (ethyne) by a radical-chain addition

10 Alkenes and Alkynes I. Ionic and Radical Addition Reactions

3CH2SCH3 from methylenecyclopentane

b.

0

II

c.CH3(CH2),CCH3 (2-decanone) from 1-octene

d.2-decanone from I-decyne

10-52" The molecular weight of a polymer obtained by radical-addition polymerization can be reduced by addition of a thiol, RSH. For example, when propenoic acid (acrylic acid) is polymerized in the presence of potassium peroxodisulfate, K2S208, adding mercaptoethanoic acid, HSCH,C02H, causes the average molecular weight of the polymer molecule to become much smaller. Draw the structure of the polymer and explain how the thiol compound functions to reduce the molecular weight. Would an alcohol do as well? Show how the potassium peroxodisulfate could function as an initiator. Would you expect it to decompose more rapidly in alkaline or strongly acid solution? Explain.

0

0

 

II

II

00-S-0-0-S-00

peroxodisulfate

 

II

II

0

0

10-53

a. 1-Bromocyclopentene adds hydrogen bromide on irradiation with ultra-

violet

light to

give 94% cis-l,2-dibromocyclopentane and 6% of the trans isomer.

Explain why Ill-dibromocyclopentane is not obtained and why the cis isomer predominates.

b. From your answer to the questions in Part a, predict the structure and stereochemistry of the major products in the following reactions:

(i)

CH3-C=C-CH3

+ 2HBr

peroxides

(ii)

CH3C=CBr + HBr

ultraviolet light

(iii)

cis-CH,CH=CHCH,

+ DBr

peroxides

(iv)

HgCI2

 

HC-CH + DCI ------+ (monoaddition product of DCI)

ALKENES AND ALKYNES ON AND REDUC

NS. AC OF ALKYNES

urther chemistry of alkenes and alkynes is described in this chapter, with emphasis on addition reactions that lead to reduction and oxidation of carboncarbon multiple bonds. First we explain what is meant by the terms reduction and oxidation as applied to carbon compounds. Then we emphasize hydrogenation, which is reduction through addition of hydrogen, and oxidative addition reactions with reagents such as ozone, peroxides, permanganate, and osmium tetroxide. We conclude with a section on the special nature of l-alkynes- their acidic behavior and how the conjugate bases of alkynes can be used in synthesis to form carbon-carbon bonds.

11-1 OXIDATION-REDUCTION OF ORGANIC COMPOUNDS

An organic compound commonly is said to be "reduced" if reaction leads to an increase in its hydrogen content or a decrease in its oxygen content. The

406

11 Alkenes and Alkynes II. Oxidation and Reduction Reactions. Acidity of Alkynes

compound would be "oxidized" if the reverse change took place:

C H 2 = C H 2 + H 2 <reduction,oxidation CH3CH3

/O\

reduction,

C H 2 = C H 2

+ [H201

H2 + HZC-

'oxidation

 

 

 

This is a very unsatisfactory definition because many oxidationreduction or redox reactions do not involve changes in hydrogen or oxygen content, as the following example illustrates:

C H 3 C l 4- Mg

CH3-Mg-Cl

(carbon is reduced; magnesium is oxidized)

Redox reactions are better defined in terms of the concept of electron transfer. Thus an atom is said to be oxidized if, as the result of a reaction, it experiences a net loss of electrons; and is reduced if it experiences a net gain of electrons. This simple definition can be used to identify oxidation or reduction processes at carbon in terms of a scale of oxidation states for carbon based on the electronegativities of the atoms attached to carbon. The idea is to find out whether in a given reaction carbon becomes more, or less, elec- tron-rich. We will use the following somewhat arbitrary rules:

1.Elementary carbon is assigned the zero oxidation state.

2.The oxidation state of any chemically bonded carbon may be as-

signed by adding -1 for each more electropositive atom and + 1 for each more electronegative atom, and 0 for each carbon atom bonded directly to the car-

bon of interest (see Figure 10-11 for the Pauling electronegativity

scale).

That is,

 

 

-1 for electropositive atoms, H, B, Na, Li, Mg

 

 

+1 for electronegative atoms, halogens, 0,N, S

 

 

0 for carbon.

 

 

The rationale for this mode of operation can be seen if we look more closely

at the example of CH3Cl+Mg -CH3-Mg-Cl.

Chlorine is more electro-

negative than either carbon or magnesium. Carbon is more electronegative than

 

6 0

6 0

magnesium. Thus CH3C1 is written properly with a polar bond asCH3----C1,

60

6 0

 

whereas the C-Mg bond is oppositely polarized,CH,----Mg.If all of the bonds were ionized completely, we could write

and it would be completely clear that carbon gains two electrons (is reduced), while magnesium loses two electrons (is oxidized). But because covalent, or at most polar, bonds actually are involved, it is much more difficult to determine whether oxidation or reduction occurs.

11-1 Oxidation-Reduction of Organic Compounds

3. In compounds with multiple bonds (

\C=O, -C=N), the at-

 

/

tached heteroatom is counted twice or three times, depending on whether the bond is double or triple.

4. A formal positive charge on carbon changes the oxidation state by +1, and a formal negative charge by -1 ; an odd electron on carbon leaves the oxidation state unchanged.

To illustrate, the oxidation state of carbon in four representative examples is determined as follows:

-I 1-1

H-C-CI

+ I 1 1 1

H

Oxidation state: 4 x (-1) = -4

Using this approach, we can construct a carbon oxidation scale, as in Table 11-1. Any reaction that increases the degree of oxidation of carbon corresponds to a loss of electrons (oxidation), and a reaction that decreases the oxidation level corresponds to a gain of electrons (reduction). Two examples follow:

-2

-2

-3

-3

CH2=CH2

> CH3-CH,

-2

-2

-1

-1

CH2=CH2

> CH2-CH2

 

 

I

I

net decrease in carbon oxidation state of 2 per molecule (reduction)

net increase in carbon oxidation state of 2 per molecule (oxidation)

We recommend this scheme of oxidation states only as an aid to identify and balance redox reactions. Also, the terminology "redox" should not be confused with the mechanism of a reaction, as there is no connection between them. A moment's reflection also will show that virtually all reactions theoretically can be regarded as redox reactions, because in almost every reaction the reacting atoms experience some change in their electronic environments. Traditionally, however, reactions are described as redox reactions of carbon only when there is a net change in the oxidation state of the carbon atoms involved. An indication of just how arbitrary this is can be seen by the example

11 Alkenes and Alkynes II. Oxidation and Reduction Reactions. Acidity of Alkynes

Table 11-1

Carbon Oxidation States of Representative Organic Compounds (R = alkyl)

Compound

carbon dioxide

tetrachloromethane isocyanates

carboxyl ic acids nitriles

ketones trichloromethane ketenes tert-alcohols aldehydes methanal dichloromethane alkanes benzene alkanes

ethyne

alkanes ethene chloromethane methanol methyl cation methyl radical alkanes methyl anion methane

Structure

Oxidation state

I1

R-C-OH

+3

 

R C z N

+3

 

R2C=0

+2

 

CHCI,

+2

 

R2C=C*=0

+2(*)

R3COH

+1

 

RCH=O

+1

 

H2C=0

0

 

CH2CI,

0

 

R4C

0

 

C6H6

-1

(per carbon)

R,CH

-1

 

HC=CH

-1

(per carbon)

R2CH2

-2

 

CH2=CH,

-2

(per carbon)

CH3CI

-2

 

CH30H

-2

 

CHP

-2

 

CH3.

-3

 

RCH,

-3

 

CH3:@

-4

 

CH4

-4

 

of addition of water to ethene. This reaction usually is not regarded as an oxidation-reduction reaction because there is no net change in the oxidation state of the ethene carbons, despite the fact that, by our rules, one carbon is oxidized and the other reduced:

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