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wheel-idea overunity.com The international free energy research forum > Mechanical setups > Gravity powered wheels > wheel-idea overunity.com The international free energy research forum prajna Jr. Member

Posts: 73

Re: wheel-idea « Reply #12 on: September 18, 2006, 11:54:13 AM » Quote Here is a wm2d model which shows what Greg was trying to explain earlier.  The red arrows show the forces on the balls (the balls exert a force in the opposite direction).  You can see that the balls on the right exert most of their force on the cam track and not on the spokes of the wheel.  Those on the left do the opposite.  Although the balls are all the same weight not all of that weight acts against the spokes.

If you were to measure the distances between opposite balls and the axis and then calculate the moments you will find that they are mostly in balance.  There is a point, when balls are at the right hand corner, that their force is not counter-acted by the track and at this point they do exert great leverage but against that you will find that there are, at that point, more balls exerting great downforce on the left (though at a shorter radius).  If there was some way to increase the nymber of balls on the right then it would work but then there would be no space for them when they get to the left.  Same old, same old problem.

In sum, the forces balance out.

 Cam_Track.gif (44.69 KB, 989x846 - viewed 48 times.)

Report to moderator   Logged Dellemann Newbie

Posts: 11

Re: wheel-idea « Reply #13 on: September 18, 2006, 12:42:22 PM » Quote prajna, thanks for your sim !

than the problem is the ramp ?

Where is the "resultat direction" ?

here the pic (the lines red and green are the sum of the distance to the axis.)

Mani

 bessler-dellemann-01.jpg (90.4 KB, 910x695 - viewed 39 times.)

Report to moderator   Logged prajna Jr. Member

Posts: 73

Re: wheel-idea « Reply #14 on: September 18, 2006, 12:56:41 PM » Quote These red arrows show the total force.  I think the resultant direction is at right angles to these arrows.  Where the arrows are short the force will be greater and where they are long it will be less (i.e. you need to invert the values.)  I hope this helps.

 Cam_Track_2.gif (36.46 KB, 902x812 - viewed 42 times.)

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